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PhpGrid is a great tool which helps to build great web application. It minimizes the development time which I never expected. My client is very pleased with outcome of the content management system that is built with it.

I am using phpMyDataGrid , and I cannot make the dropdown list menu in a column.

This line doesn't work:

I get the following error:

Warning: Invalid argument supplied for foreach() in /Applications/XAMPP/xamppfiles/htdocs/stem/phpmydatagrid.class.php on line 1079

line from 1077 to 1085 are following

And the FormatColumn() function is like this:

Anybody can help? Thanks in advance

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1 Answer

On phpmydatagrid, when using a query as data input mask, the statement shall follow the pattern bellow:

Besides that, the parameter shall have the 'select:' prefix.As an example, your statement should read:

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